曲线y=x3-4x+2在点(1,-1)处的切线方程为(  )A.x-y-2-0

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问题 曲线y=x3-4x+2在点(1,-1)处的切线方程为(  )A.x-y-2-0B.x-y=0C.x+y=0D.x+y-2=0

选项 A.x-y-2-0
B.x-y=0
C.x+y=0
D.x+y-2=0

答案 C

解析
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