设y=(4x+4)/x^2-2,则曲线在拐点处的切线方程为(  )。A.y+26

题库2022-08-02  5

问题 设y=(4x+4)/x^2-2,则曲线在拐点处的切线方程为(  )。A.y+26/9=-2(x+1)/27B.y+26/9=-4(x+1)/27C.y+26/9=-4(x+3)/27D.y+26/9=-2(x+3)/27

选项 A.y+26/9=-2(x+1)/27
B.y+26/9=-4(x+1)/27
C.y+26/9=-4(x+3)/27
D.y+26/9=-2(x+3)/27

答案 C

解析
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