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[img]2014m9x/ct_egreqj_egreqbj_0016_20148[/img] [br] AIn this question you are g
[img]2014m9x/ct_egreqj_egreqbj_0016_20148[/img] [br] AIn this question you are g
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2025-02-24
26
管理
问题
[br]
选项
答案
A
解析
In this question you are given that machine R, working alone at its constant rate, produces x units of a product in 30 minutes. Since it is easy to see that 3 hours is 6 times 30 minutes, you can conclude that Quantity A is 6x.
You can compare 6x with Quantity B in two ways.
One: In the additional information centered above the quantities, you are given that machine S, working alone at its constant rate, produces x units of the product in 48 minutes, so you can conclude that machine S can produce 6x units of the product in(6)(48)minutes, or 4.8 hours. So in 4 hours, machine S produces less than 6x units, and Quantity B is less than 6x.
Two: First, convert 48 minutes to 4/5 hour, then find the number of 48-minute periods there are in 4 hours by computing
= 5. Thus, Quantity B is 5x.
Either way, Quantity A is greater than Quantity B, and the correct answer is Choice A.
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