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  3. [img]2014m9x/ct_egreqm_egreqjs_0041_20148[/img]The expressions in the table abo

[img]2014m9x/ct_egreqm_egreqjs_0041_20148[/img]The expressions in the table abo

游客2025-02-24  38
问题
The expressions in the table above give the distance from Centerville to each of two trains t hours after 12:00 noon. At what time after 12:00 noon will the trains be equidistant from Centerville?
选项 A、0.0625
B、0.145833
C、0.215278
D、0.368056
E、0.479167
答案 B
解析 The distance between the freight train and Centerville at ? hours past noon is -10t + 115. The distance between the passenger train and Centerville at ? hours past noon is -20t + 150. To find out at what time the distances will be the same you need to equate the two expressions and solve for t as follows.
-10t + 115 = -20t + 150
10t+ 115 = 150
10t = 35
t = 3.5
Therefore, the two trains will be the same distance from Centerville at 3.5 hours past noon, or at 3:30. The correct answer is Choice B.
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