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In a certain card game, an ace counts one point, face cards count ten points, an
In a certain card game, an ace counts one point, face cards count ten points, an
游客
2025-02-23
24
管理
问题
In a certain card game, an ace counts one point, face cards count ten points, and all other cards count their face values. A player must play at least one card on each turn, and his score on a turn is determined by the total point value of the cards played. If a player holds the cards shown above’ one heart ace, one club 2, one diamond 4, one heart 6 and one heart 8), how many different point totals are possible for him on his next turn?
选项
A、5
B、22
C、10
D、20
E、21
答案
E
解析
题目首先告诉你如何计算牌的点数,A(ace)算一点,花牌(J,Q,K为face cards)算十点,其他牌则是牌面上有几点就算几点,比如说红桃4就算4点,黑桃8为8点。牌手每一轮至少要出1张牌,现在牌手一共有5张牌(一张红桃ace,一张梅花2,一张方块4,一张红桃6和一张黑桃8),题目问他下一轮出牌可能共有多少点?他下一轮出牌,可能出一张,也可能出2张,3张,4张或者5张全部出,单出1张就有1,2,4,6,8点,如果出两张,那么就可能得到3,5,7,9,6,8,10,12,14点;已经出现了重复的点数。仔细观察,这道题中最后得到的结果是连续的数字。5张牌点数最多为l+2+4+6+8=21点,最少为1点,因此下一轮牌手出牌的点数有21种。正确答案为E。
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