2. 职称英语
  3. There are several possible relationships between language and society.One i

There are several possible relationships between language and society.One i

游客2024-11-27  28
问题     There are several possible relationships between language and society.
One is what social structure may either influence or determine linguistic struc-【M1】______
ture and/or behavior. A certain evidence may be adduced to support this【M2】______
view: the age-grading phenomenon whereby young children speak differently
from elder children and, in turn, children speak differently from mature【M3】______
adults: studies which show that the varieties of language that speakers use
reflect such matters like their regional, social, or ethnic origin: and other【M4】______
studies which show that particular ways of speaking, choices of words, and
even rules for conversing are in fact highly determined by certain social
requirements.
    A second possible relationship is directly opposing to the first: linguistic【M5】______
structure and/or behavior may either influence or determine social structure.
Many of these who argue that languages rather than speakers of these【M6】______
languages can be "sexist". A third possible relationship is that the influence is
bi-directional: language and society may influence each. A fourth possibility【M7】______
is to assume that there is no relationship at all between linguistic structure and
social structure and that every is independent of the other. A variant of this【M8】______
possibility would be to say that, although there might be some such relationship,
present attempts to characterize it is essentially premature, given what【M9】______
we know about both language and society. Actually, this variant view appears
to be the one that Chomsky himself holds: he prefers to develop an asocial
linguistics such as a preliminary to any other kind of linguistics.【M10】______ [br] 【M1】
选项
答案 what—that
解析 连词错误。该句为表语从句，be动词后面的部分为从句，由于句中不缺失任何成分，故用that来引导从句。
转载请注明原文地址:https://tihaiku.com/zcyy/3863127.html
相关试题推荐
随机试题
最新回复(0)