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Consider a probability experiment with events M, N, and L for which P(M) = 0.25,
Consider a probability experiment with events M, N, and L for which P(M) = 0.25,
游客
2024-01-12
42
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问题
Consider a probability experiment with events M, N, and L for which P(M) = 0.25, P (N) = 0.35, and P (L) = 0.80. Suppose that events M and N are mutually exclusive and events N and L are independent. What are the probabilities P (M or N) and P (N or L)?
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答案
0.60,0.87
解析
已知M和N互斥,即P(M and N)=0,P(M or N)=P(M)+P(N)-P(M and N)=0.25+0.35-0=0.60。已知N和L独立,则P(N and L)=P(N)×P(L)=0.35×0.80=0.28,P(N or L)=P(N)+P(L)-P(N and L)=0.35+0.80-0.28=0.87。
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