图示电路中,已知L1=0.12H,ω=314rad/s,u1(t)=U1mcos

admin2022-08-02  21

问题 图示电路中,已知L1=0.12H,ω=314rad/s,u1(t)=U1mcos(ωt)+U3mcos(3ωt),u2(t)=U1mcos(ωt),C2和C2的数值分别为下列哪种数值(  )A.7.39μF和71.14μFB.71.14μF和7.39μFC.9.39μF和75.14μFD.75.14μF和9.39μF

选项 A.7.39μF和71.14μF
B.71.14μF和7.39μF
C.9.39μF和75.14μF
D.75.14μF和9.39μF

答案 C

解析 根据输出电压只含有基频分量,可知基频时,发生串联谐振;三次谐频时,发生并联谐振,则:
①三次频率时(电路发生并联谐振,电容电感并联回路相当于断路):1/(3ωC1)=3ωL1,因此,C1=1/(9ω2L1)=1/(9×3142×0.12)=9.39×10-6F=9.39μF。
②基频时(电路发生串联谐振,回路相当于短路):容抗XC1=(ωC1)-1=314×9.39×10-6=339Ω,感抗XL1=ωL1=314×0.12=37.68Ω,则XL1∥XC1=j37.68∥(-j339)=j42.39Ω。又因为XC2+XL1∥XC1=0,所以电容C2=1/(314×42.39)=75.13×10-6F=75.13μF。
转载请注明原文地址:https://tihaiku.com/jzgc/274142.html

最新回复(0)